# Electrolyseur et pile à combustible en classe

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$VH2 (consommé)=20 cm3$
$VH2 (calculé)=JE.·t·R.·Tz·F.·p=0,21UNE.·712s·8,314Jmole-1K-1·298K2·96.485C.mole-1·1,013·105Pennsylvanie$
$VH2 (calculé)=18,96·10−6 m3=18,96 cm3$
$??Faraday=18,96 cm320 cm3=0,948≈95 %$